What is the difference between ++I and I++ in C?
What is the difference between ++i and i++ in c? In C, ++ and -- operators are called increment and decrement operators. They are unary operators needing only one operand. Hence ++ as well as -- operator can appear before or after the operand with same effect. That means both i++ and ++i will be equivalent. both will make i=6.
What is the meaning of a [i] [j] in C?
The meaning is the semantics given in the C standard, and that semantics is type-independent. Consider that a [i] [j] is also equivalent to i [a] [j] and j [i [a]], regardless of the types of a, i, and j.
What is the value of % in C programming?
The % operator in C is the “modulo” operator, which has the same precedence as the * (multiply) and / (divide) operators. Its value is the remainder of the integer division of its two operands. For example, if x is 13, then the value of “x % 2” would be 1, since 13 divided by 2 is 6 with remainder 1.
What is the difference between I++ and C++ variable increment operators?
Additionally, a C student doing C++ might like that was taught to him if he wrote i++ on a complex type that can't be removed by the compiler. The only difference is the order of operations between the increment of the variable and the value the operator returns.
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What does I mean in C language?
%i takes integer value as integer value with decimal, hexadecimal or octal type. To enter a value in hexadecimal format – value should be provided by preceding “0x” and value in octal format – value should be provided by preceding “0”.
What is the meaning of i ++ in C?
post incrementi++ is post increment because it increments i 's value by 1 after the operation is over. Let's see the following example: int i = 1, j; j = i++; Here value of j = 1 , but i = 2 . Here the value of i will be assigned to j first, and then i will be incremented. ++i.
What is %d used for in C?
Format specifiers define the type of data to be printed on standard output....Format Specifiers in C.SpecifierUsed For%da decimal integer (assumes base 10)%ia decimal integer (detects the base automatically)%oan octal (base 8) integer13 more rows•Jan 22, 2020
What is I and J in C programming?
It is a variable that contains the address of other variable ( i in this case). Since j is a variable the compiler must provide it space in the memory. Once again, the following memory map would illustrate the contents of i and j. As you can see, i's value is 3 and j's value is i's address.
What does i ++ stand for?
The accepted answer at [...], and I've seen this language in many other places as well, is that, "i++ means 'tell me the value of i, then increment', whereas ++i means 'increment i, then tell me the value'.
What is the difference between -- I and I --?
There is no difference in your case. --i is pre-decrement and i-- is post-decrement.
What is %d in printf?
In C programming language, %d and %i are format specifiers as where %d specifies the type of variable as decimal and %i specifies the type as integer. In usage terms, there is no difference in printf() function output while printing a number using %d or %i but using scanf the difference occurs.
What is %s in printf?
%s and string We can print the string using %s format specifier in printf function. It will print the string from the given starting address to the null '\0' character. String name itself the starting address of the string. So, if we give string name it will print the entire string.
What is void main in C?
The void main() indicates that the main() function will not return any value, but the int main() indicates that the main() can return integer type data. When our program is simple, and it is not going to terminate before reaching the last line of the code, or the code is error free, then we can use the void main().
Why do loops use I?
Generally the i in for loops stands for iterator, that's why most of programmers use i instead of other names. i and j are just a variable name, you can use any variable name like a, b, c,x, y or number, length etc.
What is int * j mean?
int *j is a declaration of a pointer to an integer. This in itself consumes a memory of 2 bytes(Borland Compiler) and points to a memory of 2 bytes(that is an integer).
How do you use i and j in a for loop?
Java Nested for Looppublic class NestedForExample {public static void main(String[] args) {//loop of i.for(int i=1;i<=3;i++){//loop of j.for(int j=1;j<=3;j++){System.out.println(i+" "+j);}//end of i.More items...
What is the meaning of the word I?
plural I's or Is\ ˈīz \ Definition of I (Entry 5 of 8) : someone aware of possessing a personal individuality : self. I. abbreviation (2)
What does == mean in C?
== is an Equal To Operator in C and C++ only, It is Binary Operator which operates on two operands. == compares value of left and side expressions, return 1 if they are equal other will it will return 0.
What is array in C?
Arrays are used to store multiple values in a single variable, instead of declaring separate variables for each value. To create an array, define the data type (like int ) and specify the name of the array followed by square brackets [].
How many operators are there in C programming?
C programming has two operators increment ++ and decrement -- to change the value of an operand (constant or variable) by 1. Increment ++ increases the value by 1 whereas decrement -- decreases the value by 1. These two operators are unary operators, meaning they only operate on a single operand.
Why is output an integer?
It is because both the variables a and b are integers. Hence, the output is also an integer. The compiler neglects the term after the decimal point and shows answer 2 instead of 2.25.
What is the result of and in C++?
For example, the bitwise AND represented as & operator in C or C++ takes two numbers as operands and does AND on every bit of two numbers. The result of AND is 1 only if both bits are 1.
What is operator in C++?
We can define operators as symbols that help us to perform specific mathematical and logical computations on operands. In other words, we can say that an operator operates the operands.#N#For example, consider the below statement:
What is the postfix version of i++?
In the postfix version (i.e., i++), the value of i is incremented, but the value of the expression is the original value of i. So basically it first assigns a value to expression and then increments the variable.
How to assign y to a value?
Assign y the value we get by evaluating the expression x++, ie, the value of x before increment then increment x.
How many expressions should be in a C compiler?
In the early C compilers, the three previous expressions may have produced different executable code depending on which one was used. Nowadays, this type of code optimization is generally performed automatically by the compiler, thus the three expressions should produce exactly the same executable code.
Why is x assigned the value 1?
Here, x is assigned the value 1, because char is a type with a size of one byte.
What is compound assignment?
Compound assignment operators modify the current value of a variable by performing an operation on it . They are equivalent to assigning the result of an operation to the first operand:
When using logical operators, C++ only evaluates what is necessary from left to right to come up with the combined?
When using the logical operators, C++ only evaluates what is necessary from left to right to come up with the combined relational result , ignoring the rest. Therefore, in the last example ( (5==5)|| (3>6) ), C++ evaluates first whether 5==5 is true, and if so, it never checks whether 3>6 is true or not. This is known as short-circuit evaluation, and works like this for these operators:
Can a constant be compared to a variable?
Of course, it's not just numeric constants that can be compared, but just any value, including, of course, variables. Suppose that a=2, b=3 and c=6, then:
Does a combined conditional expression increase i?
Here, the combined conditional expression would increase i by one, but only if the condition on the left of && is true, because otherwise, the condition on the right-hand side ( ++i<n) is never evaluated.
